nate7723 (guest)

Sat Feb 11, 2012 6:04 am

There was some discussion about this a year ago

Here's the link, and a relevant quote

http://forums.ninja250.org/posting.php?mode=topicreview&t=84153&tro=1

Quote:

FrugalNinja250 Posted: 21 Feb 2011 09:46 Here's what I came up with: The speedometer hub gear ratio is 23:9; For every 23 turns of the front wheel the speedo cable turns 9 times. The first gear set inside the speedo head has a ratio of 10:1; for every 10 turns of the speedo cable the cross shaft spins 1 time. The second gear set has a ratio of 16:1, so every 16 turns of the cross shaft turns the longitudinal shaft 1 time. The last gear set ratio is 14:1; every 14 rotations of the longitudinal shaft turns the 10ths wheel of the odometer 1 time. If you do the math, the overall ratio between the wheel and odometer is (14*16*10*9)/23, or ~876.5:1.

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• update on springs! — taygold, Fri Feb 10, 2012 10:47 am

  • There was some discussion about this a year ago — nate7723, Sat Feb 11, 2012 6:04 am

  • Start a new thread in the Classic forum. Someone might know. (n/t) — Bokonon, Fri Feb 10, 2012 7:34 pm